Clarke Earley, Ph.D.
Department of Chemistry
Kent State University Stark Campus
North Canton, OH 44720
The periodic table can be used to predict the ground state electron configuration of atoms and the charge of many atoms in ionic compounds. Metals have a relatively small number of electrons in their outermost (valence) shell. In ionic compounds, metals lose these electrons to form positively-charged ions called cations. The valence shell of non-metals is almost filled, so non-metals tend to gain electrons to form negatively-charged ions called anions.
| Charge | +1 | +2 | ? | ? | ? | ? | ? | ? | ? | ? | ? | ? | (+3) | ? | -3 | -2 | -1 | 0 |
| 1 | 18 | |||||||||||||||||
| Row 1 | H | 2 | 13 | 14 | 15 | 16 | 17 | He | ||||||||||
| Row 2 | Li | Be | B | C | N | O | F | Ne | ||||||||||
| Row 3 | Na | Mg | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | Al | Si | P | S | Cl | Ar |
| Row 4 | K | Ca | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn | Ga | Ge | As | Se | Br | Kr |
| Row 5 | Rb | Sr | Y | Zr | Nb | Mo | Tc | Ru | Rh | Pd | Ag | Cd | In | Sn | Sb | Te | I | Xe |
| Row 6 | Cs | Ba | La | Hf | Ta | W | Re | Os | Ir | Pt | Au | Hg | Tl | Pb | Bi | Po | At | Rn |
| Row 7 | Fr | Ra | Ac | Db | Jl | Rf | Bh | Hn | Mt | 110 | 111 | |||||||
| . | ||||||||||||||||||
| s1 | s2 | d1 | d2 | d3 | d4 | d5 | d6 | d7 | d8 | d9 | d10 | p1 | p2 | p3 | p4 | p5 | p6 | |
| s-block | (row-1) d-block | p-block | ||||||||||||||||
For example, calcium (Ca) has an electron configuration of
... 4s2
Loss of these two electrons gives the Ca+2 ion.
Polyatomic ions are combinations of two or more atoms held together by covalent bonds that have a charge. The following table needs to be memorized.
| Ammonium | NH4+1 | Hydroxide | OH-1 | ||||
| Nitrite | NO2-1 | Sulfite | SO3-2 | Phosphate | PO4-3 | ||
| Nitrate | NO3-1 | Sulfate | SO4-2 | Phosphate | PO4-3 | ||
| Bisulfate | HSO4-1 | Hydrogen Phosphate | HPO4-2 | ||||
| Carbonate | CO3-2 | Bicarbonate | HCO3-1 | Dihydrogen Phosphate | H2PO4-1 |
Definitions
Although ionic compounds contain charged paticles, they have a total charge of zero. For this to happen, the total positive charge must be equal in magnitude to the total negative charge.
For example, in calcium chloride, the ions Ca+2 and Cl-1 are present. To balance the +2 charge of Ca+2, two chloride (Cl-1) ions are required. Thus, the formula of calcuim chloride is CaCl2.
All salts have a total charge of zero. To determine the charge on the transition metal in a salt of known formula. Determine the total negative charge. The total positive charge will be equal to this, which should be divided equally between all of the transition metals present.
For example, in V2O5, the oxygen anion has a charge of -2 (O-2). The total negative charge is 5*(-2)=-10. Thus, the total positive charge must be +10. Dividing this positive charge on each of the two vanadium atoms must be 10/2 = +5 (V+5).
For polyatomics, the same procedure can be used. In Ni3(PO4)2, the total negative charge is 2*(-3)=-6. Thus, the total positive charge is +6, and the charge on each nickel ion must be +6/3=2 (Ni+2).