**Vertex Coloring**

Let G be a graph with no loops. A *k*-coloring of G is an assignment of
*k*
colors to the vertices of G in such a way that adjacent vertices are assigned
different colors. If G has a *k*-coloring, then G is said to be
*k*-coloring, then
G is said to be *k*-colorable. The chromatic number of G, denoted by
X(G), is the smallest number *
k* for
which is *k*-colorable. For example,

3-coloring

4-coloring

5-coloring

Not a permissible coloring, since one of the edge has color blue at both ends.

It is easy to see from above examples that chromatic number of G is at least 3. That is X(G) ≤ 3, since G has a 3-coloring in first diagram. On the other hand, X(G) ≥ 3, since G contains three mutually adjacent vertices (forming a triangle)., which must be assigned different colors. Therefore, we have X(G) = 3.

**Lower Bound of
X(G) **

To obtain a lower bound for X(G), we look for the largest complete subgraph in G. For example, consider the following graph.

Since this graph contains the complete graph K_{4}, therefore
X(G) ≥ 4.

**Upper Bound of
X(G)**

To obtain an upper bound for X(G), we note that if G has n vertices, then X(G) ≤ 4. However, this upper bound is very poor and we can improve it if we know the largest vertex-degree in G, which gives us the following theorem.

**Theorem 1**
*If G is a simple graph whose maximum vertex-degree is d, then
X(G) ≤ d+1.*

* Proof Idea
*Mathematical induction on the number of vertices of G.

We can prove the following slightly stronger theorem, which illustrates the same idea.

**Brook's Theorem 2 **
*Let G be a connected simple graph whose maximum vertex-degree is d. If G is
neither a cycle graph with an odd number of vertices, nor a complete graph,
then
X(G) ≤ d.*

To illustrate the use of Brook's theorem, consider graph G.

Since G contains the complete graph K_{4}, so
X(G) ≤ 4. On the other hand, G
satisfies the conditions of Brook's theorem with d=4 and so
X(G) ≤ 4. It follows from these two
pieces of information that
X(G) = 4.

It is important to note that Brook's theorem does not always give a tight
bound. For example, if G is the bipartite graph k_{1,100}, then
X(G) = 2, whereas Brook's theorem
gives us the upper bound
X(G) ≤ 100.

**Chromatic Polynomials**

All known algorithms for finding the chromatic number of a graph are some what inefficient. A good estimation for the chromatic number of given graph involves the idea of a chromatic polynomials.

Let G be a simple graph, and let P_{G}(k) be the number of ways of
coloring the vertices of G with k colors in such a way that no two adjacent
vertices are assigned the same color. The function P_{G}(k) is called
the chromatic polynomial of G.

As an example, consider complete graph K_{3} as shown in the
following figure.

Then the top vertex
can be assigned any of the k colors, the left vertex can be assigned any k-1
colors, and right vertex can be assigned any of the k-2 colors. The chromatic
polynomial of K_{3} is therefore k(k-1)(k-2). The extension of this immediately
gives us the following result.

If G is the complete graph K_{n}, then P_{G}(k) =
k(k - 1)(k - 2) . . . (k - n +1).

**Edge Colorings**

Let G be a graph with no loops. A *k*-edge-coloring of G is an assignment of
*k *colors to the edges of G in such a way that any two edges meeting at a
common vertex are assigned different colors,. If G has a *k*-edge coloring, then
G is said to be *k*-edge colorable. The chromatic index of G, denoted by
X`(G), is the smallest *
k* for which G
is *k*-edge-colorable. For example, consider the
following graphs with eight edges:

4-edges-coloring

5-edge-coloring

6-edge-coloring

Not a permissible coloring. Since two of the edges colored blue meet at a common vertex

From the above examples, it follows that X`(G) ≤ 4, since G has a 4-edge-coloring in figure a (above). On the other hand, X`(G) ≥ 4, since G contains 4 edges meeting at a common vertex i.e., a vertex of degree 4, which must be assigned different colors. Therefore, X`(G) = 4.

**Lower Bound of
X`(G) **

To obtain a lower bound for X`(G), we look for the largest vertex-degree, d, in given G, which gives us X`(G) ≥ d.

**Upper Bound of
X`(G) **

To obtain an upper bound for
X`(G), we note that if G has *
m* edges,
then
X`(G) ≤ *m*.

However, this upper bound is very poor and has been improved by V. G. Vizing and C. E. Shannon.

**Vizing's Theorem 4 ***
If G is a simple graph whose maximum vertex-degree is d, then D ≤
X`(G) ≤ d+1. Following two theorems
give upper bounds for the chromatic index of a graph with multiple edges.*

**Vizing's Theorem for Multiple Edges
***If G is a graph whose maximum vertex-degree is d, and if h is the maximum
number of edges joining a pair of vertices, then d ≤
X`(G) ≤ d+h.*

For example, consider the following graph in which d = 6 and h = 3.

Therefore bounds are 6 ≤ X`(G) ≤ 9.

In fact, X`(G) = 8 for this particular graph.

**Shannon's Theorem ***
If G is a graph whose maximum vertex-degree is d, then d ≤
X`(G) ≤ 3/2 d.*

For example, consider the following graph we have d = 6, and so bounds are 6 ≤ X`(G) ≤ 9. If d is odd, then (3/2)d is not an integer. In which case we can strengthen the bound to (3/2)d - 1/2.

We consider this section with an important theorem by Hungarian mathematician Denes Konig.

**Konig's Theorem **
* If G is n bipartite graph whose maximum vertex degree is d, then X`(G) = d*.

** Proof Idea
**Mathematical induction on the number of edge of G.

Konig's theorem tells us that every bipartite graph (not necessarily simple) with maximum vertex-degree d can be edge-colored with just d colors.

** **